Inflatable Wading
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![]() Intex Ocean Play Center Kids Inflatable Wading Pool US $49.95
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![]() Intex Rainbow Ring Inflatable Wading Pool Play Center US $80.00
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![]() Jungle Play Center Inflatable Wading Kiddie Pool Toy US $80.00
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![]() Countryside Play Center Inflatable Wading Pool Toy Game US $34.00
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![]() Pinwheel Pool Inflatable Kids Swimming Wading Swim New US $49.99
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![]() Colorful 84 by 84 x 21 Deep Inflatable Wading Pool US $24.00
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A few items from Amazon
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Intex Recreation Swim Center Family Pool, Age 6+ $21.99 Cool off this summer in the Swim Center(tm) inflatable family pool from Intex(tm). It measures 103" x 69" with a 22" depth, and both air chambers are designed with a double-valve intake and a free-flow exhaust valve. Inflation is quick and easy, and the package includes a repair patch.... |
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Intex Recreation 48X10 2 Ring 59421Ep Circles Pools $6.14 48' x 10', 2 Ring Pool, 8 Gauge, Repair Patch Included, Star Graphics,... |
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Poolmaster 52505 Poolside Towel Tree $19.29 WARNING: CHOKING HAZARD - Small parts. Not for children under 3 years. The portability of the Poolmaster® poolside towel tree keeps towels and swim accessories nearby and ready to use. You can easily hang wet towels, swimsuits, accessories, and other sport clothing on the 3 bars divided into 6 sections.... |
help me~~2 problems!?
1. To water the yard you use a hose with a radius of 3.5 cm. Water flows from the hose with a speed of 1.3 m/s. If you partially block the end of the hose so the effective radius is now 0.55 cm, with what speed does water spray from the hose?
...............m/s
2. To fill a child's inflatable wading pool, you use a garden hose with a radius of 3 cm. Water flows from this hose with a speed of 1.9 m/s. How long will it take to fill the pool to a depth of 30 cm if it is circular and has a radius of 1.7 m?
..........minutes
the mass flow rate remains constant
m-dot = kg/s=rho (density)* A(cross section area) * v (speed)
a) rho A1 v1 = rho A2 v2
v2 = A1 v1/A2 = pi r1^2 v1/ pi r2^2 = r1^2 v1/ r2^2
v2 = (r1/r2)^2 * v1 = (3.5/0.55)^2 * 1.3 m/s
v2 = 52.64 m/s
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b) mass flow rate = m-dot = kg/sec = rho Av
volume flow rate = m-dot / rho = Av
volume V = A v time
V = pi (0.03)^2 * 1.9 * t ----(1)
V = pi R^2 * h = pi (1.7)^2 * 0.3 >>> (1)
pi (1.7)^2 * 0.3 = pi (0.03)^2 * 1.9 * t
t = (1.7)^2 * 0.3 / (0.03)^2 * 1.9 = 507 sec
t = 8.45 minutes


US $49.95




